2+x^2-(-2x)=x-2-(-1-x^2)

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Solution for 2+x^2-(-2x)=x-2-(-1-x^2) equation: 



2+x^2-(-2x)=x-2-(-1-x^2)

We move all terms to the left:

2+x^2-(-2x)-(x-2-(-1-x^2))=0

We get rid of parentheses

x^2-(x-2-(-1-x^2))+2x+2=0



We calculate terms in parentheses: -(x-2-(-1-x^2)), so:

x-2-(-1-x^2)

determiningTheFunctionDomain
-(-1-x^2)+x-2

We get rid of parentheses

x^2+x+1-2

We add all the numbers together, and all the variables

x^2+x-1

Back to the equation:

-(x^2+x-1)



We add all the numbers together, and all the variables

x^2+2x-(x^2+x-1)+2=0

We get rid of parentheses

x^2-x^2+2x-x+1+2=0

We add all the numbers together, and all the variables

x+3=0

We move all terms containing x to the left, all other terms to the right

x=-3

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